# The perimeter of a rectangle is 18 feet, and the area of the rectangle is 14 square feet, what is the width & length?

Let l be the lengty and b be the width of the rctangle. $2 \cdot l + 2 \cdot b = 18$ (given) and $l \cdot b = 14$ (given) $l + b = 9 \mathmr{and} l = 9 - b$ Now $\left(9 - b\right) \cdot b = 14 \mathmr{and} 9 \cdot b - {b}^{2} = 14 \mathmr{and} {b}^{2} - 9 \cdot b + 14 = 0 \mathmr{and} \left(b - 7\right) \left(b - 2\right) = 0 \therefore b = 2 \mathmr{and} 7$when b=2 ; l=9-2=7 when b=7; l=9-7=2[Ans]