# The screen on Jeff's computer monitor has a length of 15.2 and a width of 11.5 in. How do you find the measure of the diagonal for Jeff's monitor?

Feb 23, 2016

$19.06$ to 2 decimal places

#### Explanation:

This forms a right triangle so you can use Pythagoras.

Let the diagonal be $d$ then we have

${d}^{2} = {\left(15.2\right)}^{2} + {\left(11.5\right)}^{2}$

$d = \sqrt{231.04 + 132.25}$

$d = 19.06$ 2 decimal places