# The sum of 3 numbers is 61. The second number is 5 times the first. While the 3rd is 2 less then the first. How do you find the numbers?

##### 1 Answer

#### Explanation:

Let's say that your numbers are

The first thing to write down is that their sum is equal to

#x + y + z = 61" " " "color(purple)((1))#

Next, you know that the second number, **five times** bigger than the first,

#y = 5 * x" " " "color(purple)((2))#

Finally, you know that if you **subtract**

#z = x - 2" " " "color(purple)((3))#

Use equations

#x + 5x + x - 2 =61#

#7x = 63 implies x = 63/7 = color(green)(9)#

Now take this value of

#y = 5 * (9) = color(green)(45)#

#z = (9) - 2 = color(green)(7)#

The three numbers are