The sum of three consecutive even integers is 228, how do you find the integers?

1 Answer
Jan 26, 2016

Answer:

#74#, #76# and #78#

Explanation:

Let the first of your integers be #x#.

As you are only looking at even integers, the next consecutive even integer would be #x + 2# and the consecutive even integer after that would be #x + 4#.

You know that their sum is #228#, so you have

#x + (x+2) + (x + 4) = 228#

#<=> color(white)(xxx) x + x + 2 + x + 4 = 228#

#<=>color(white)(xxxxxxxxxxx) 3x + 6 = 228#

Subtract #6# from both sides of the equation:

#<=> 3x = 222#

Divide by #3# on both sides of the equation:

#<=> x = 74#

Thus, your consecutive even integers are #74#, #76# and #78#.