The sum of three consecutive odd integers is 351, how do you find the three integers?

2 Answers
May 4, 2018

Answer:

I got: #115,117 and 119#

Explanation:

let us call our integers:
#2n+1#
#2n+3#
#2n+5#
we get:
#2n+1+2n+3+2n+5=351#
rearrange:
#6n=351-9#
so that:
#n=342/6=57#
our integers will then be:
#2n+1=115#
#2n+3=117#
#2n+5=119#

May 4, 2018

Answer:

115, 117 & 119

Explanation:

We can represent the three integers by using the variable #x#

1st odd integer #=x#
2nd odd integer #=x+2# consecutive integers would be #x+1#
3rd odd integer #=x+4#

The sum means we need to add

#x + x +2 + x + 4 = 351#

Combine like terms
#3x + 6 = 351#

Use additive inverse to isolate the variable term
#3x cancel(+6) cancel(-6)= 351-6#

#3x = 345#

Use the multiplicative inverse to isolate the variable
#(cancel3x)/cancel3 = 345/3#

#x =115#
#x+2=117#
#x + 4 = 119#