The velocity of an object with a mass of #3 kg# is given by #v(t)= 3 t^2 - 5 t #. What is the impulse applied to the object at #t= 2 #?

1 Answer
Dec 19, 2015

Answer:

#6"N.s"#

Explanation:

The impulse is the average force x time

The average force id given by:

#F_((ave))=(mDeltav)/t#

So the impulse = #mDeltav/cancel(t)xxcancel(t)#

#=mDeltav#

#v(t)=3t^2-5#

So after 2s:

#v=3xx2^2-5xx2=2"m/s"#

Assuming the impulse is over a period of 2s then #Deltav=2"m/s"#

#:.# Impulse#=3xx2=6"N.s"#