Question

The velocity of an object with a mass of `3 kg` is given by `v(t)= 6 t^2 -4 t`. What is the impulse applied to the object at `t= 3`?

Answer 1

`F*t=3*42=126 N.s`

Explanation:

`F=(d P)/(d t)`
`F*d t=d P`
`F*d t=d(m v)`
`F*d t=m d v`
`d v=(12t-4)*d t`
`F*d t=m*(12t-4)*d t`
`int F*d t=int m*(12t-4)*d t`
`F*t=m int (12t-4)*d t`
`F*t=3(6t^2-4t)`
`F*t=3(54-12)`
`F*t=3*42=126 N.s`