The velocity of an object with a mass of $3 kg$ is given by $v(t)= sin 8 t + cos 9 t$ . What is the impulse applied to the object at $t= ( 7 pi)/ 12$ ?

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Answer 1 · 2018-03-04T08:02:55

Impulse is defined as change in momentum,

So,here change in momentum in between $t=0$ to $t=(7pi)/12$ is,

$m(v-u) =3{(sin (8*(7pi)/12) - sin 0 +cos (9*(7pi)/12)-cos 0}=3*(-0.83)=-2.5 Kg.ms^-1$

The velocity of an object with a mass of 3 kg3 kg is given by v(t)= sin 8 t + cos 9 t v(t)= sin 8 t + cos 9 t . What is the impulse applied to the object at t= ( 7 pi)/ 12 t= ( 7 pi)/ 12 ?