Question

The velocity of an object with a mass of `3 kg` is given by `v(t)= sin 8 t + cos 9 t`. What is the impulse applied to the object at `t= ( 7 pi)/ 12`?

Answer 1

Impulse is defined as change in momentum,

So,here change in momentum in between `t=0` to `t=(7pi)/12` is,

`m(v-u) =3{(sin (8*(7pi)/12) - sin 0 +cos (9*(7pi)/12)-cos 0}=3*(-0.83)=-2.5 Kg.ms^-1`