# The volume of a gas is 250.0 mL when the pressure is 1.00 atm. At the same temperature, what is the pressure at which the volume of the gas is 80 mL?

Jun 7, 2016

The new Pressure would be $3.125 a t m$

#### Explanation:

In order to solve this problem we will use Boyle's Law which is the relationship between Pressure and Volume at a fixed temperature.

The equation is ${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

${P}_{1} = 1 a t m$
${V}_{1} = 250 m L$
P_2=?
${V}_{2} = 80 m L$

$\left(1 a t m\right) \left(250 m L\right) = {P}_{2} \left(80 m L\right)$

$\frac{\left(1 a t m\right) \left(250 \cancel{m L}\right)}{80 \cancel{m L}} = \frac{{P}_{2} \left(\cancel{80 m L}\right)}{\cancel{80 m L}}$

$3.125 a t m = {P}_{2}$