The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii. If a can with a six-inch radius holds pints, how many gallons will a similar can with a 24-inch radius hold?

Question

7056 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-07-30T02:33:59

$color(brown)(V_2 = 8 " gallons"$

$"Volume of cylinder " = V = pi r^2 h$

Let $r_1, h_1$ be the radius and height of the first cylinder and $r_2, h_2$ the second.

$color(purple)(r_1 = 6 " inch", r_2 = 24 " inch", V_1 = 1 " pint"$

$V_1 = pi r_1^2 h_1, V_2 = pi r_2 ^2 h_2$

$V_2 / V_1 = r_2 ^3 / r_1 ^3 = 24^3 / 6^3, " given"$

$1 gallon = 8 pints$

$:. V_2 = (24/6)^3 * V_1 = (24/6)^3 * 1 = 4^3 = 64 " pints"$

$color(brown)(V_2 = 64 / 8 = 8 " gallons, as 8 pints = 1 gallon"$