# Twice the smallest of three consecutive odd integers is seven more than the largest, how do you find the integers?

##### 2 Answers

#### Answer:

Interpret the question and solve to find:

#11# ,#13# ,#15#

#### Explanation:

If the smallest of the three integers is

#2n = (n+4)+7 = n+11#

Subtract

#n = 11#

So the three integers are:

#### Answer:

The three consecutive odd integers are

#### Explanation:

We are given **3 consecutive odd integers**.

Let the first odd integer be

Then the next odd integer will be

**Since #x# is odd, #x+1# will be even**, and we want 3 odd integers that are consecutive.

The

Now, We have our three integers,

Clearly the smallest integer is

Given that: **twice the smallest = 7 more than the largest**.

**Checking**

Our 3 consecutive odd integers are

Twice the smallest =

7 more than the largest =