Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa. The temperature of the gas is raised to 273 degrees Celsius and the pressure is increased to 600 kPa. What is the new volume?

Well, $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$...temperature is specified to be absolute...$0 \cdot K = - 273.15 \cdot K$
We solve for....${V}_{2} = \frac{{P}_{1} {V}_{1}}{T} _ 1 \times {T}_{2} / {P}_{2}$
=(150*kPaxx200*L)/(273*K)xx(546*K)/(600*kPa)=??*L