# Two motorcycles A and B depart simultaneously from opposite location toward one another 50km apart. The have 120km/h and 80km/h. Determine time the meet and distance travelled?

Apr 21, 2016

$0.25 h \mathmr{and} 30 k m$ from $A$ towards $B$

#### Explanation:

Motorcycle $A \mathmr{and} B$ are $50 k m$ apart.
Speed of $A = 120 k m / h$, towards $A$
Speed of $B = 80 k m / h$, towards $B$.
Suppose they meet after time $t$
Distance traveled by $A = 120 \times t$
Distance traveled by $B = 80 \times t$
Total distance traveled by both$= 120 t + 80 t = 200 t$
This distance traveled must be $= \text{Distance between the two} = 50 k m$

Equating both
$200 t = 50$, Solving for $t$
$t = \frac{50}{200} = 0.25 h$
Distance traveled by $A = 120 \times 0.25 = 30 k m$, towards $B$