Two opposite sides of a parallelogram each have a length of #10 #. If one corner of the parallelogram has an angle of #(3pi)/8 # and the parallelogram's area is #15 #, how long are the other two sides?

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Answer 1 · 2018-05-22T03:32:27

Other two parallel sides are #color(crimson)(1.62)# long each

Area of parallelogram #A = a b sin theta#

Given : #Area = 15, a = 10, theta = (3pi)/8#

#10 * b * sin ((3pi)/8) = 15#

#b = 15 / (10 * sin ((3pi)/8)#

#b = 1.62#