Question

Two opposite sides of a parallelogram each have a length of `12`. If one corner of the parallelogram has an angle of `(3pi)/8` and the parallelogram's area is `72`, how long are the other two sides?

Answer 1

`=6.5`

Explanation:

Area of the parallelogram is `=ab sin theta` where `a=12` is the side and `theta=(3pi)/8` and we have to find `b=?`
Therefore
Area`=72=12b sin((3pi)/8)`
or
`bsin((3pi)/8)=72/12`
or
`b(0.924)=6`
or
`b=6.5`