Question

Two opposite sides of a parallelogram each have a length of `16`. If one corner of the parallelogram has an angle of `(11 pi)/12` and the parallelogram's area is `72`, how long are the other two sides?

Answer 1

`b=17.4`

Explanation:

Area of the parallelogram is `=ab sin theta` where `a=16` is the side and `theta=(11pi)/12` and we have to find `b=?`
Therefore
Area`=72=16b sin((11pi)/12)`
or
`bsin((11pi)/12)=72/16`
or
`b(0.2588)=9/2`
or
`b=17.4`