Two opposite sides of a parallelogram each have a length of #2 #. If one corner of the parallelogram has an angle of #(7 pi)/8 # and the parallelogram's area is #5 #, how long are the other two sides?

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Answer 1 · 2018-01-09T12:09:35

Other two sides are #6.53# unit long.

The area of the parallelogram is #A_p=s_1*s_2*sin theta#

Where #s_1=2,s_2=?,theta=(7pi)/8=157.5^0 # are the adjacent

sides and corner angle respectively.

#A_p=5 :. 5=2*s_2*sin157.5 or s_2= 5/(2*sin157.5)# or

#s_2 ~~6.53# unit. Other two sides are #6.53# unit long. [Ans]