Two opposite sides of a parallelogram each have a length of #7 #. If one corner of the parallelogram has an angle of #(2 pi)/3 # and the parallelogram's area is #28 #, how long are the other two sides?

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Answer 1 · 2018-05-22T11:36:45

Other two sides are #4.62# unit long.

The area of the parallelogram is #A_p=s_1*s_2*sin theta#

Where #s_1=7,s_2=?,theta=(2 pi)/3=120^0 # are the adjacent

sides and corner angle respectively.

#A_p=28 :. 28=7*s_2*sin 120 or s_2= 28/(7*sin 120)# or

#s_2 ~~4.62(2 dp)# unit.

Other two sides are #4.62# unit long. [Ans]