Question

Two opposite sides of a parallelogram have lengths of `12`. If one corner of the parallelogram has an angle of `pi/8` and the parallelogram's area is `36`, how long are the other two sides?

Answer 1

Other two sides are `7.84(2dp)` unit long.

Explanation:

We know the area of the parallelogram as `A_p=s_1*s_2*sin theta`
Here `s_1 =12 ; theta=pi/8=180/8=22.5^0 ; A_p=36 :. 36=12*s_2*sin22.5 or s_2=36/(12 *sin22.5) =3/sin22.5=7.84(2dp)`unit[Ans]