Two rhombuses have sides with lengths of #1 #. If one rhombus has a corner with an angle of #(5pi)/12 # and the other has a corner with an angle of #(7pi)/12 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2016-08-20T11:55:23

Area of the rhombus with angle #theta=(5pi)/12# and Side #a=1# is
#=a^2 sin theta#

#=1^2 sin((5pi)/12)#

#=1(0.966)#

#=0.966#

Area of the rhombus with angle #theta=(7pi)/12# and Side #a=1# is

#=a^2 sin theta#

#=1^2 sin((7pi)/12)#

#=1(0.966)#

#=0.966#

So difference in Area#=0.966-0.966=0#