Question

Two rhombuses have sides with lengths of `1`. If one rhombus has a corner with an angle of `pi/12` and the other has a corner with an angle of `(3pi)/4`, what is the difference between the areas of the rhombuses?

Answer 1

Difference in areas between the two rhombuses is 0.4483

Explanation:

Area of rhombus `= (1/2) * d_1 * d_2 or a * h`
Where `d_1 , d_2` are the diagonals, a is the side and h is the altitude.

In this case we will use the formula Area = a * h.

Rhombus 1
`h = a sin theta = 1 * sin ((pi)/12) = 0.2588`
Area = a * h = 1 * 0.2588 = 0.2588#

Rhombus 2
`h = a sin theta = 1 * sin ((3pi)/4) = 0.7071`
Area = a * h = 1 * 0.7071 = 0.7071#

Hence the difference in areas is `0.7071 - 0.2588= 0.4483`