Two rhombuses have sides with lengths of #3 #. If one rhombus has a corner with an angle of #(7pi)/8 # and the other has a corner with an angle of #(pi)/6 #, what is the difference between the areas of the rhombuses?

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Answer 1 · 2016-08-23T11:53:30

#=1.05#

Area of the rhombus with angle #theta=(7pi)/8# and Side #a=3# is
#=a^2 sin theta#

#=3^2 sin((7pi)/8)#

#=9(0.383)#

#=3.45#

Area of the rhombus with angle #theta=(pi)/6# and Side #a=3# is

#=3^2 sin theta#

#=3^2 sin((pi)/6)#

#=9(0.5)#

#=4.5#

So difference in Area#=4.5-3.45=1.05#