Question

Two rhombuses have sides with lengths of `7`. If one rhombus has a corner with an angle of `(pi)/2` and the other has a corner with an angle of `(3pi)/4`, what is the difference between the areas of the rhombuses?

Answer 1

`=14.35`

Explanation:

Area of the rhombus with angle `theta=(pi)/2` and Side `a=7` is
`=a^2 sin theta`
`=7^2 sin((pi)/2)`
`=49(1)`
`=49`
Area of the rhombus with angle `theta=(3pi)/4` and Side `a=7` is
`=a^2 sin theta`
`=7^2 sin((3pi)/4)`
`=49(0.707)`
`=34.65`
So difference in Area`=49-34.65=14.35`