# Using the Pythagorean theorem how would you find A if b = 11, c = 17?

Mar 19, 2017

See the entire solution process below:

#### Explanation:

The Pythagorean Theorem states:

${a}^{2} + {b}^{2} = {c}^{2}$

Substituting for $b$ and $c$ and solving gives:

${a}^{2} + {11}^{2} = {17}^{2}$

${a}^{2} + 121 = 289$

${a}^{2} + 121 - \textcolor{red}{121} = 289 - \textcolor{red}{121}$

${a}^{2} + 0 = 168$

${a}^{2} = 168$

$\sqrt{{a}^{2}} = \sqrt{168}$

$a = \sqrt{168} = 12.961$ rounded to the nearest thousandth.