WeUsing the x-intercept and y-intercept, how do you graph #2x-3y=5#?

2 Answers
Dec 4, 2016

Answer:

graph{2x-3y=5 [-10, 10, -5, 5]}

#equation: y=(2x-5)/3#

Explanation:

the equation can be converted into #y=mx+c#:

#2x - 3y = 5#

(-2x)

#-3y = -2x + 5#

(/3)

#-y= (-2x+5)/3#

(*-1)

#y= -(-2x+5)/3#

#y= (2x-5)/3#

Dec 4, 2016

Answer:

#"Plot the points " (0,-5/3)" and " (5/2,0)#

Explanation:

When the line with given equation crosses the y-axis the corresponding x-coordinate at this point will be zero.
Substituting x = 0 into the equation gives the y-intercept.

#(2xx0)-3y=5rArr-3y=5rArry=-5/3#

#rArr(0,-5/3)" is the point on the y-axis"#

Similarly when the line crosses the x-axis the corresponding
y-coordinate at this point will be zero. Substituting y = 0 into the equation gives the x-intercept.

#2x-(3xx0)=5rArr2x=5rArrx=5/2#

#rArr(5/2,0)" is the point on the x-axis"#

Plot these 2 points and draw a straight line through them.
graph{2/3x-5/3 [-10, 10, -5, 5]}