Question

What are 4 consecutive odd integers whose sum is 64?

Answer 1

`13,15,17,19`

Explanation:

Let the first number be `color(red)(x`

Remember that consequetive odd integers differ in the values of `2`

`:.` The other numbers are `color(red)(x+2,x+4,x+6`

`color(orange)(rarrx+(x+2)+(x+4)+(x+10)=64`

Remove the brackets

`rarrx+x+1+x+2+x+4+x+6=64`

`rarr4x+12=64`

`rarr4x=64-12`

`rarr4x=52`

`color(blue)(rArrx=52/4=13`

So the first integer is `13`

Then the other integers are `(x+2),(x+4),(x+6)`

That are `color(green)(15,17,19`