What are 4 consecutive odd integers whose sum is 64?

1 Answer
Mar 20, 2016

Answer:

#13,15,17,19#

Explanation:

Let the first number be #color(red)(x#

Remember that consequetive odd integers differ in the values of #2#

#:.# The other numbers are #color(red)(x+2,x+4,x+6#

#color(orange)(rarrx+(x+2)+(x+4)+(x+10)=64#

Remove the brackets

#rarrx+x+1+x+2+x+4+x+6=64#

#rarr4x+12=64#

#rarr4x=64-12#

#rarr4x=52#

#color(blue)(rArrx=52/4=13#

So the first integer is #13#

Then the other integers are #(x+2),(x+4),(x+6)#

That are #color(green)(15,17,19#