# What are the asymptote(s) and hole(s), if any, of  f(x) =(1-e^-x)/x ?

Oct 2, 2016

The only asymptote is $x$=0

#### Explanation:

Of course, $x$ cannot be 0, otherwise $f \left(x\right)$ remains undefined. And that's where the 'hole' in the graph is.