What are the excluded values of #f(t) = (t+1)/(t^2+3t+2)#?

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Answer 1 · 2016-09-04T00:38:47

#t!=-2, -1#

These will occur when the denominator is rendered #0#.

We can find the excluded values by setting the denominator to #0# and solving for the variable.

#t^2 + 3t + 2 = 0#

#(t + 2)(t + 1) = 0#

#t = -2 and -1#

Hence, #t!= -2 and -1#.

Hopefully this helps!