# What are the extrema and saddle points of #f(x)=2x^2 lnx#?

##### 1 Answer

Mar 21, 2018

The domain of definition of:

is the interval

Evaluate the first and second derivatives of the function:

The critical points are the solutions of:

and as

In this point:

so the critical point is a local minimum.

The saddle points are the solutions of:

and as

graph{2x^2lnx [-0.2943, 0.9557, -0.4625, 0.1625]}