What are the factors of #25(x+y)^2-16#? Algebra Polynomials and Factoring Factor Polynomials Using Special Products 1 Answer Perihelion · Stefan V. Mar 10, 2018 #(5x + 5y - 4) (5x + 5y + 4)# Explanation: Using, #a^2 - b^2 = (a - b) (a + b)# ,factor the expression #(5 (x + y) - 4) xx (5 (x + y) + 4)# Distribute #5# through the parenthesis #(5x + 5y - 4) xx (5x + 5y + 4)# Answer link Related questions How do you factor special products of polynomials? How do you identify special products when factoring? How do you factor #x^3 -8#? What are the factors of #x^3y^6 – 64#? How do you know if #x^2 + 10x + 25# is a perfect square? How do you write #16x^2 – 48x + 36# as a perfect square trinomial? What is the difference of two squares method of factoring? How do you factor #16x^2-36# using the difference of squares? How do you factor #2x^4y^2-32#? How do you factor #x^2 - 27#? See all questions in Factor Polynomials Using Special Products Impact of this question 1832 views around the world You can reuse this answer Creative Commons License