# What are the factors of 2m^3+3m^2+4m+6?

Nov 9, 2014

$2 {m}^{3} + 3 {m}^{2} + 4 m + 6$

by factoring ${m}^{2}$ out of the first two terms and $2$ out of the last two terms,

$= {m}^{2} \left(2 m + 3\right) + 2 \left(2 m + 3\right)$

by factoring out $2 m + 3$,

$= \left({m}^{2} + 2\right) \left(2 m + 3\right)$

Hence, its factors are $\left({m}^{2} + 2\right)$ and $\left(2 m + 3\right)$.

I hope that this was helpful.