Alkanes: CnH2n+2;
Alkene: CnH2n;
Alkyne: CnH2n−2;
Alkyl residue: CnH2n+1;
Aldehyde/ketone: CnH2nO;
Cycloalkane: CnH2n
A fully saturated hydrocarbon, an alkane, has general formula CnH2n+2: n=1, methane; n=2, ethane; n=3, propane. BY reason of their formula alkanes are said to HAVE NO DEGREES of UNSATURATION.
Where the formula is CnH2n or CnH2nOm, each 2 hydrogens LESS than 2n+2 represents a degree of unsaturation. Each degree of unsaturation represents a double bond OR a ring. Compare cyclopropane to propane or hexane to cyclohexane to cyclohexene; does this formulation hold?
Where there is nitrogen in the formula we substract NH from the given formula before assessing its degree of saturation. For methylamine, H3CH2CNH2, we assess a formula of C2H6, no degrees of saturation. For pyridine, C5H5N, we assess C5H4, 4∘ of unsaturation, i.e. 3 olefinic bonds, and one ring..........