What are the intercepts for #2x-y=1#?

2 Answers
Mar 25, 2018

Answer:

(0.5, 0) and (0, -1)
graph{2x-y=1 [-10, 10, -5, 5]}

Explanation:

I would always recommend sketching the graph yourelf if you can.

If you can't plot the graph yourself, substitute #x=0# and #y=0# into your equation to find the value of the other variable at that point.
(because graph intercepts #y#-axis when #x=0# and #x#-axis when #y=0#).

At #y=0#, #2x-0=1#, which rearranges to #x=0.5#, by dividing both sides by 2. Hence intercept 1 is (0.5, 0)

At #x=0#, #2(0)-y=1#, which rearranges to #y=-1# by multiplying both sides by -1. Hence, intercept 2 is (0, -1)

Hope this helps!

Mar 25, 2018

Answer:

#"x-intercept "=1/2," y-intercept "=-1#

Explanation:

#"to find the intercepts, that is where the graph crosses"#
#"the x and y axes"#

#• " let x = 0, in the equation for y-intercept"#

#• " let y = 0, in the equation for x-intercept"#

#x=0rArr0-y=1rArry=-1larrcolor(red)"y-intercept"#

#y=0rArr2x-0=1rArrx=1/2larrcolor(red)"x-intercept"#
graph{(y-2x+1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y+1)^2-0.04)=0 [-10, 10, -5, 5]}