# What are the intercepts for 2x-y=1?

Mar 25, 2018

(0.5, 0) and (0, -1)
graph{2x-y=1 [-10, 10, -5, 5]}

#### Explanation:

I would always recommend sketching the graph yourelf if you can.

If you can't plot the graph yourself, substitute $x = 0$ and $y = 0$ into your equation to find the value of the other variable at that point.
(because graph intercepts $y$-axis when $x = 0$ and $x$-axis when $y = 0$).

At $y = 0$, $2 x - 0 = 1$, which rearranges to $x = 0.5$, by dividing both sides by 2. Hence intercept 1 is (0.5, 0)

At $x = 0$, $2 \left(0\right) - y = 1$, which rearranges to $y = - 1$ by multiplying both sides by -1. Hence, intercept 2 is (0, -1)

Hope this helps!

Mar 25, 2018

$\text{x-intercept "=1/2," y-intercept } = - 1$

#### Explanation:

$\text{to find the intercepts, that is where the graph crosses}$
$\text{the x and y axes}$

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

$x = 0 \Rightarrow 0 - y = 1 \Rightarrow y = - 1 \leftarrow \textcolor{red}{\text{y-intercept}}$

$y = 0 \Rightarrow 2 x - 0 = 1 \Rightarrow x = \frac{1}{2} \leftarrow \textcolor{red}{\text{x-intercept}}$
graph{(y-2x+1)((x-1/2)^2+(y-0)^2-0.04)((x-0)^2+(y+1)^2-0.04)=0 [-10, 10, -5, 5]}