What are the intercepts for #y= - 2/3x - 12#?

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Answer 1 · 2018-05-23T01:05:50

x-intercept is: #x=-18#
y-intercept is: #y=-12#

#y= - 2/3x - 12#

This is in the slope point form #y=mx+b#, m is the slope and b is the y-intercept.

#m=-2/3#

#b = -12#

So y-intercept is: #y=-12#

to find the x-intercept set #y=0# and solve for #x#:

#0= - 2/3x - 12#

#12= - 2/3x#

#x=-18#

So x-intercept is: #x=-18#

graph{- 2/3x - 12 [-29.75, 10.25, -15.12, 4.88]}