What are the intercepts of #-10x-9y=25#?

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Answer 1 · 2016-03-08T05:19:56

The intercepts are:

#x# -intercept #(-5/2, 0)#

#y# intercept #(0, 25/9)#

Note: There are two type of intercepts , the #x# and #y#

a) #x# intercept, is when #y = 0#

b) #y# intercept, is when #x = 0# .

#--------------#

To find the intercepts of #-10x -9y = 25#

1) Let's find #x# intercept, #y=0#

#-10x -9(0) = 25#

#-10 x = 25 " " # then solve for x

#x = -25/10 = -5/2#

x-intercepts #(-5/2 , 0)#

2) Let's find #y# intercept, #x= 0#

# -10(0) -9y = 25#

#-9y = -25#

#y = 25/9#

#y# intercept #(0, 25/9)#