What are the intercepts of 3y+4x=1?

Apr 21, 2016

$\text{intercepts=} \left\{\frac{1}{4} , \frac{1}{3}\right\}$

Explanation:

$3 y + 4 x = 1$
$3 y = - 4 x + 1$
$y = - \frac{4}{3} x + \frac{1}{3}$

$\text{for y intercept is x=0}$
$y = - \frac{4}{3} \cdot 0 + \frac{1}{3}$

$y = \frac{1}{3}$

$\text{for x intercept is y=0}$

$0 = - \frac{4}{3} x + \frac{1}{3}$

$\frac{4}{\cancel{3}} x = \frac{1}{\cancel{3}}$

$x = \frac{1}{4}$

$\text{intercepts=} \left\{\frac{1}{4} , \frac{1}{3}\right\}$