# What are the intercepts of 5x+3y=-7?

Equation of x-axis is $y = 0$
So putting $y = 0$ in the given eqn we will get intercept from x- axis
$\therefore 5 \cdot x + 3 \cdot 0 = - 7 \implies x = - \frac{7}{5}$
Similarly,Equation of y-axis is $x = 0$
So putting $x = 0$ in the given eqn we will get intercept from y- axis
$5 \cdot 0 + 3 \cdot y = - 7 \implies y = - \frac{7}{3}$
hence the intercepts are $- \frac{7}{5}$ and $- \frac{7}{3}$