# What are the intercepts of -6y+8x=1?

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#### Explanation:

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May 24, 2017

The intercepts are: $\left(\frac{1}{8} , 0\right) \mathmr{and} \left(0 , - \frac{1}{6}\right)$

#### Explanation:

In order to find the $x - \mathmr{and} y -$intercepts, evaluate the other variable at $0$

So, if you put $x = 0$, the function becomes: $- 6 y + 8 \left(0\right) = 1$,

or just $- 6 y = 1$. Now divide by $- 6$ and you will get:

$y = - \frac{1}{6.}$ This is the $y$-intercept.

Next, evaluate the function for $y = 0 \text{ } \rightarrow - 6 \left(0\right) + 8 x = 1$

$8 x = 1 \text{ }$ Divide by $8$ to get:

$x = \frac{1}{8}$. This is the $x$-intercept.

So, the points are: $\left(\frac{1}{8} , 0\right) \mathmr{and} \left(0 , - \frac{1}{6}\right) .$

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