What are the intercepts of #7x+16y=4#? Algebra Graphs of Linear Equations and Functions Intercepts and the Cover-Up Method 1 Answer sankarankalyanam Apr 14, 2018 #color(indigo)("x-intercept " = a = 4/7, " y-intercept " = b = 1/4# Explanation: #7x + 16y = 4# Intercept form of standard equation is #x / a + y / b = 1# #(7/4)x + (16/4) y = 1# #x / (4/7) + y / (1/4) = 1# #color(indigo)("x-intercept " = a = 4/7, " y-intercept " = b = 1/4# Answer link Related questions How do you use the cover-up method to solve for the x and y intercept? What are the intercepts for horizontal and vertical line graphs? What are the intercepts for #3x-4y=-5#? How do I determine the x and y intercept for the graph #6(x-1)=2(y+3)#? How do you graph #5x+y=5# using the intercepts? What needs to be done to the equation #3(x+2)=2(y+3)# before you can use either method to find... What are the intercepts for the #y=0# and #x=0# graphs? How do you sketch a graph with x-intercept of 1 and y-intercept of -5? How do you graph #2x - 3y = 9# using x- and y- intercepts? How do you use the intercepts to graph the equation #2x-4y=8#? See all questions in Intercepts and the Cover-Up Method Impact of this question 1800 views around the world You can reuse this answer Creative Commons License