# What are the intercepts of -7x+4y=13?

##### 1 Answer
Jan 7, 2016

$x$ intercept:

(-13/7;0)

$y$ intercept:

(0;13/4)

#### Explanation:

you have to write the expression in the form:

$y = f \left(x\right)$

$4 y = 7 x + 13$

$y = \frac{7}{4} \cdot x + \frac{13}{4}$

$x$ intercept:

$y = 0$

then:

$\frac{7}{4} \cdot x + \frac{13}{4} = 0$

$\frac{7}{4} \cdot x = - \frac{13}{4}$

$7 x = - 13$

$x = - \frac{13}{7}$

then the $x$ intercept point is

(-13/7;0)

$y$ intercept:

$x = 0$

$y = \frac{7}{4} \cdot 0 + \frac{13}{4}$

$y = 0 + \frac{13}{4} = \frac{13}{4}$

Then the $y$ intercept point is:

(0;13/4)