# What are the intercepts of 7y-4x=18?

$\left(0 , \frac{18}{7}\right) \left(- \frac{9}{2} , 0\right)$
Put $x = 0 \mathmr{and} y = 0$ to find the relevant points
When $x = 0$. $7 y = 18$ so $y = \frac{18}{7}$
When $y = 0$. $- 4 x = 18$ so $x = \frac{18}{- 4}$. =$- \frac{9}{2}$