What are the intercepts of #-8y+4x=9#?

1 Answer
Jan 1, 2016

Answer:

The intercepts are the points at which the function crosses the axis.

Explanation:

This means that, at such points, one of the coordinates of the intersection point, by definition, HAS to be zero. That is so because when a coordinate is zero, it means the point lies on the axis.

If #x=0#, then #-8y+cancel(4(0))=9 => y=-9/8#

If #y=0#, then #cancel(-8(0))+4x=9 => x=9/4#

The intercepts are, then, #A (0;-9/8)# and #B (9/4;0)#

graph{-8y+4x=9 [-3.99, 3.987, -1.994, 1.994]}