# What are the intercepts of -x+3y=-3?

Mar 6, 2018

The x-intercept is $\left(3 , 0\right)$.

The y-intercept is $\left(0 , - 1\right)$.

#### Explanation:

Given:

$- x + 3 y = - 3$ is a linear equation in standard form:

$A x + B y = C$.

X-intercept: value of $x$ when $y = 0$.

Substitute $0$ for $y$ and solve for $x$.

$- x + 3 \left(0\right) = - 3$

$- x = - 3$

Multiply both sides by $- 1$.

$x = 3$

The x-intercept is $\left(3 , 0\right)$.

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Y-intercept: value of $y$ when $x = 0$

Substitute $0$ for $x$ and solve for $y$.

$0 + 3 y = - 3$

$3 y = - 3$

Divide both sides by $3$.

$\frac{{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1} y}{{\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1}} = - {\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1} / {\textcolor{red}{\cancel{\textcolor{b l a c k}{3}}}}^{1}$

$y = - 1$

The y-intercept is $\left(0 , - 1\right)$.

You can graph this equation by plotting the x- and y-intercepts and drawing a straight line through them.

graph{-x+3y=-3 [-11.25, 11.25, -5.625, 5.625]}