What are the intercepts of #-x-4y=11#?

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Answer 1 · 2018-03-25T04:05:09

The x-intercept is #(-11,0)#.

The y-intercept is #(0,-11/4)# or #(0,-2.75)#.

Given:

#-x-4y=11#

Multiply by #-1#. This will reverse the signs.

#x+4y=-11#

The x-intercept is the value of #x# when #y=0#.

Substitute #0# for #y#.

#x+4(0)=-11#

#x=-11#

The x-intercept is #(-11,0)#.

The y-intercept is the value of #y# when #x=0#.

Substitute #0# for #x#.

#0+4y=-11#

#4y=-11#

Divide both sides by #4#.

#y=-11/4=-2.75#

The y-intercept is #(0,-11/4)# or #(0,-2.75)#.

graph{(-x-4y-11)(x+4y+11)=0 [-10, 10, -5, 5]}