# What are the possible number of positive real, negative real, and complex zeros of y= (2-x)(3-2x)?

Jul 30, 2015

I found two:
$x = 2$
$x = \frac{3}{2}$

#### Explanation:

If you set $y = 0$ you get:
$\left(2 - x\right) \left(3 - 2 x\right) = 0$
this is tru when:
$2 - x = 0$ or $x = 2$
and
$3 - 2 x = 0$ or $x = \frac{3}{2}$
these are the zeros of your function.