What are the products of the following antimarkovnikov reaction: $C H_{3} - C (C H_{3}) = C H - C H_{3} + H B r + H_{2} O_{2}$ $CH_3-C(CH_3)=CH-CH_3 + HBr + H_2O_2$ ?

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Answer 1 · 2015-01-05T19:43:06

The product is 2-bromo-3-methylbutane, (CH₃)₂CH-CHBr-CH₃.

In a Markovnikov addition of HBr, the H adds to the alkene carbon that has more H atoms (C-3).

(CH₃)₂C=CH-CH₃ + HBr → (CH₃)₂CBr-CH₂-CH₃

In an anti-Markovnikov addition of HBr, the H adds to the alkene carbon that has fewer H atoms (C-2).

(CH₃)₂C=CH-CH₃ + HBr → (CH₃)₂CH-CHBr-CH₃

What are the products of the following antimarkovnikov reaction: CH3−C(CH3)=CH−CH3+HBr+H2O2CH_3-C(CH_3)=CH-CH_3 + HBr + H_2O_2 ?