# Why is a noncarbocation intermediate necessary for an antimarkovnikov halogenation to happen?

Anti-Markovnikov addition to a $\pi$ bond requires the addition of the non-hydrogen group to the less substituted carbon.
When we have a radical initiator, like $H O O H$, we can ensure that the radical intermediate (that has had the halogen added to the $\pi$ bond, already, picture below) becomes the most stable which will undergo hydrogen abstraction with $H B r$.