Question

What are the reducing and oxidizing agents in the equation? If there are none, write “no redox reaction" (include oxidation states for each element in the equation)

Answer 1

`"Ferric ion"` is reduced..........

Explanation:

And `"oxalate ion"` is oxidized to carbon dioxide.

`"Reduction half equation:"`

`Fe^(3+) + e^(-) rarr Fe^(2+)` `(i)`

`"Oxidation half equation:"`

`""^(+III)C_2O_4^(2-) rarr 2CO_2 +2e^(-)` `(ii)`

For each equation, MANIFESTLY, both charge and mass are balanced, as they must be if they reflect chemical reality, and the final redox equation takes `2xx(i) + (ii):`

`2Fe^(3+) + C_2O_4^(2-)rarr 2Fe^(2+) +2CO_2(g)uarr`

Are charge and mass balanced here? Don't trust my arithmetic!