Question

What are the roots of the equation: z² + 4z + 8 = 0, where z can be of the form ai + b?

Answer 1

It is

#z^2+4z+8=0=>z^2+4z+4+4=0=>(z+2)^2-4i^2=0=> (z+2+2i)*(z+2-2i)=0#

Hence the roots are `z_1=-2-2i` and `z_2=-2+2i`