# What are the roots of the equation: z² + 4z + 8 = 0, where z can be of the form ai + b?

z^2+4z+8=0=>z^2+4z+4+4=0=>(z+2)^2-4i^2=0=> (z+2+2i)*(z+2-2i)=0
Hence the roots are ${z}_{1} = - 2 - 2 i$ and ${z}_{2} = - 2 + 2 i$