What are the six trig function values of #-135#?

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Answer 1 · 2018-03-17T06:01:47

As below.

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#hat (-135) = -(3pi)/4 = 2pi - (3pi)/4 = (5pi)/4#

Angle falls in III quadrant where only #tan, cot# are positive.

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#sin ((5pi)/4) = sin (pi + (pi/4)) = - sin (pi/4) = - 1/sqrt2#

#csc ((5pi)/4) = csc (pi + (pi/4)) = - csc (pi/4) = - sqrt2#

#coc ((5pi)/4) = cos (pi + (pi/4)) = - cos (pi/4) = - 1/sqrt2#

#sec ((5pi)/4) = sec (pi + (pi/4)) = - sec (pi/4) = - sqrt2#

#tan ((5pi)/4) = tan (pi + (pi/4)) = tan (pi/4) = 1#

#cot ((5pi)/4) = cot (pi + (pi/4)) = cot (pi/4) = 1#